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Suppose $C/\mathbb{F}_q$ is a curve of genus g. The easiest type of curve to look at are hyperelliptic curves $y^2=f(x)$ where $f(x)$ has degree $2g+1$. Suppose $C/\mathbb{F}_q$ is a curve of genus g. The easiest type of curve to look at are hyperelliptic curves
$y^2=f(x)$ where $f(x)$ has degree $2g+1$.
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References: Yui, Voloch, References: [[attachment:yui-on_the_jacobian_of_hyperelliptic_curves_over_fields_of_characteristic_p_gt_2.pdf|Yui]], Voloch,

Possible reference http://www.math.colostate.edu/~pries/Preprints/00DecPreprints/08groupschemeconm1007.pdf


Cartier matrix and Hasse-Witt Matrix: [[attachment:final final M and N.sws|Best and most up to date!]]


Alternative exponentiation f^((p-1)/2). So far not faster. [[attachment:alternative exponentiation of f.sws]]

See [[http://demo.sagenb.org/home/pub/64/|this published version]].

Title: Computation of p-torsion of Jacobians of hyperelliptic curves

Abstract: An elliptic curve defined over a finite field of characteristic p can be ordinary or supersingular; this distinction measures certain properties of its p-torsion. The p-torsion of the Jacobian of a curve of higher genus can also be studied and classified by interesting combinatorial invariants, such as the p-rank, a-number, and Ekedahl-Oort type. Algorithms to compute these invariants exist but have not been implemented. In this talk, I will explain how to compute these invariants and describe the lag in producing explicit curves with given p-torsion invariants.

Project

\mathbb{F}_q, q = p^a, then E/\mathbb{F}_q can be ordinary or supersingular. Some ways to determine this implemented in Sage: a_p, newton_slopes of Frobenius_polynomial, Hasse_invariant.

Suppose C/\mathbb{F}_q is a curve of genus g. The easiest type of curve to look at are hyperelliptic curves y^2=f(x) where f(x) has degree 2g+1. The p-torsion of its Jacobian has invariants generalizing the ordinary/supersingular distinction. These are called p-rank, a-number, Ekedahl-Oort type, etc. Its Jacobian also has a Newton polygon (the length of slope 0 portion equals the p-rank). The Newton polygon has been implemented for hyperelliptic curves in Sage for large p. The easiest type of curve to look at is y^2 = f(x) where f(x) has degree 2g+1.

To compute some of these: set up y^2 = f(x), raise f(x)^{(p-1)}{2} = \sum c_i x^i. Create the (g\times g) matrix M = (c_{p*i-j}) (the ijth entry is the coefficient of x^{pi-j}). Look at the g by g matrix,

M^{(p^i)} = (c_{p*i-j}^{p^i})

(take the p^ith power of each coefficient and create N = M M^{(p)} M^{(p^2)} ... M^{(p^{g-1})}.

The matrix M is the matrix for the Cartier operator on the 1-forms. The p-rank is the rank of N. The a-number equals g-rank(M).

For the Ekedahl-Oort type you need the action of F and V on the deRham cohomology (more difficult).

Test cases: y^2=x^p-x (p-rank 0, and (if I remember correctly) a-number (p-1)/2).

Some questions: for genus 4 (or higher), and given prime - is there a curve of p-rank 0 and a-number 1.

I will describe more motivation and questions on Thursday.

References: Yui, Voloch,

Possible reference http://www.math.colostate.edu/~pries/Preprints/00DecPreprints/08groupschemeconm1007.pdf

Cartier matrix and Hasse-Witt Matrix: Best and most up to date!

Alternative exponentiation f^((p-1)/2). So far not faster. alternative exponentiation of f.sws

See this published version.

days26/Pries Project (last edited 2010-12-15 03:33:47 by GaganSekhon)